What is the tangent of f(x)=(1+5x)^{12},(0,1) ?

The tangent of f(x)=(1+5x)^{12},(0,1) is y=60x+1

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tangent of f(x)=(1+5x)^{12},(0,1)

tangent of

f (x) = (1 + 5 x)^{12}, (0, 1)

y = 60 x + 1

Solution steps

Find the slope of

f (x) = (1 + 5 x)^{12} : \frac{df ( x )}{d x} = 60 (1 + 5 x)^{11}

Compute the slope of

f (x) = (1 + 5 x)^{12}

(0, 1) : m = 60

Find the line with slope m=

60

and passing through

(0, 1) : y = 60 x + 1

y = 60 x + 1

10 y^{^{'}} = 10 \cdot 9.81 - 5 y

y = \frac{1}{x - 1}, at x = 6

y^{^{''}} - 4 y^{^{'}} + 3 y = 0

\frac{d}{d x} (- 10 sin (2 x + 10))

y^{^{''}} + 25 y = - 20 sin (5 t)

What is the tangent of f(x)=(1+5x)^{12},(0,1) ?
The tangent of f(x)=(1+5x)^{12},(0,1) is y=60x+1