What is the derivative of acos^2(x)+bx ?

The derivative of acos^2(x)+bx is -asin(2x)+b

What is the first derivative of acos^2(x)+bx ?

The first derivative of acos^2(x)+bx is -asin(2x)+b

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derivative of

a cos^{2} (x) + b x

- a sin (2 x) + b

Solution steps

\frac{d}{d x} (a cos^{2} (x) + b x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos^{2} (x)) + \frac{d}{d x} (b x)

\frac{d}{d x} (a cos^{2} (x)) = - a sin (2 x)

\frac{d}{d x} (b x) = b

= - a sin (2 x) + b

\int (sin (x) - 4 cos (x)) d x

\int \frac{x + 3}{( x - 1 ) ( x ^{2} + 1 )} d x

\frac{d}{d x} (ln (3 x + 4))

x \to 6 + lim (x 6 - x)

x \to 0 lim ((x) sin (\frac{1}{x}))

What is the derivative of acos^2(x)+bx ?
The derivative of acos^2(x)+bx is -asin(2x)+b
What is the first derivative of acos^2(x)+bx ?
The first derivative of acos^2(x)+bx is -asin(2x)+b