What is the derivative of (x^4+2^{cos(x)}) ?

The derivative of (x^4+2^{cos(x)}) is (-sin(x)ln(x^4+2)+(4x^3cos(x))/(x^4+2))(x^4+2)^{cos(x)}

What is the first derivative of (x^4+2^{cos(x)}) ?

The first derivative of (x^4+2^{cos(x)}) is (-sin(x)ln(x^4+2)+(4x^3cos(x))/(x^4+2))(x^4+2)^{cos(x)}

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\frac{d}{d x} ((x^{4} + 2)^{c o s (x)})

(- sin (x) ln (x^{4} + 2) + \frac{4 x ^{3} cos ( x )}{x ^{4} + 2}) (x^{4} + 2)^{c o s (x)}

Solution steps

\frac{d}{d x} ((x^{4} + 2)^{c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

(x^{4} + 2)^{c o s (x)} = e^{c o s (x) l n (x^{4} + 2)}

= \frac{d}{d x} (e^{c o s (x) l n (x^{4} + 2)})

Apply the chain rule:

e^{c o s (x) l n (x^{4} + 2)} \frac{d}{d x} (cos (x) ln (x^{4} + 2))

= e^{c o s (x) l n (x^{4} + 2)} \frac{d}{d x} (cos (x) ln (x^{4} + 2))

\frac{d}{d x} (cos (x) ln (x^{4} + 2)) = - sin (x) ln (x^{4} + 2) + \frac{4 x ^{3} cos ( x )}{x ^{4} + 2}

= e^{c o s (x) l n (x^{4} + 2)} (- sin (x) ln (x^{4} + 2) + \frac{4 x ^{3} cos ( x )}{x ^{4} + 2})

e^{c o s (x) l n (x^{4} + 2)} = (x^{4} + 2)^{c o s (x)}

= (- sin (x) ln (x^{4} + 2) + \frac{4 x ^{3} cos ( x )}{x ^{4} + 2}) (x^{4} + 2)^{c o s (x)}

x \to - 3 lim (x^{3})

y^{^{''}} + 9 y = 2 sec (3 t)

\frac{d}{d x} (\frac{i}{x})

\frac{d}{d x} (6 (sec (x) + tan (x))^{\frac{3}{2}})

\frac{\partial}{\partial x} (x^{5} sin (y))

What is the derivative of (x^4+2^{cos(x)}) ?
The derivative of (x^4+2^{cos(x)}) is (-sin(x)ln(x^4+2)+(4x^3cos(x))/(x^4+2))(x^4+2)^{cos(x)}
What is the first derivative of (x^4+2^{cos(x)}) ?
The first derivative of (x^4+2^{cos(x)}) is (-sin(x)ln(x^4+2)+(4x^3cos(x))/(x^4+2))(x^4+2)^{cos(x)}