What is the integral of 7cos(x)-4/(sqrt(1-x^2)) ?

The integral of 7cos(x)-4/(sqrt(1-x^2)) is 7sin(x)-4arcsin(x)+C

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integral of 7cos(x)-4/(sqrt(1-x^2))

\int 7 cos (x) - \frac{4}{1 - x ^{2}} d x

7 sin (x) - 4 arcsin (x) + C

Solution steps

\int 7 cos (x) - \frac{4}{1 - x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 cos (x) d x - \int \frac{4}{1 - x ^{2}} d x

\int 7 cos (x) d x = 7 sin (x)

\int \frac{4}{1 - x ^{2}} d x = 4 arcsin (x)

= 7 sin (x) - 4 arcsin (x)

Add a constant to the solution

= 7 sin (x) - 4 arcsin (x) + C

sin (3 t) e^{4 t}

\int sin (\frac{1}{2}) x d x

e^{6}, e^{x}, x = 0

x \to + 2 - lim (\frac{∣ x - x ∣}{x - 2})

\frac{d y}{d x} = \frac{3 x}{3 + x ^{2}}

What is the integral of 7cos(x)-4/(sqrt(1-x^2)) ?
The integral of 7cos(x)-4/(sqrt(1-x^2)) is 7sin(x)-4arcsin(x)+C