What is (\partial)/(\partial y)(x+y) ?

The answer to (\partial)/(\partial y)(x+y) is 1

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(\partial)/(\partial y)(x+y)

\frac{\partial}{\partial y} (x + y)

1

Solution steps

\frac{\partial}{\partial y} (x + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 + 1

Simplify

= 1

(x^{2} y^{4} + x^{6}) d x - x^{3} y^{3} d y = 0

t y^{^{''}} - y^{^{'}} = 0

\frac{\partial}{\partial x} (\frac{2 x y}{x ^{2} + y ^{2}})

\int \frac{3}{2} t + 1 d t

\frac{d}{d x} (\frac{5 x ^{2} tan ( x )}{sec ( x )})

What is (\partial)/(\partial y)(x+y) ?
The answer to (\partial)/(\partial y)(x+y) is 1