What is (\partial)/(\partial x)(-6e^xcos(yz)) ?

The answer to (\partial)/(\partial x)(-6e^xcos(yz)) is -6cos(yz)e^x

Popular >

(\partial)/(\partial x)(-6e^xcos(yz))

\frac{\partial}{\partial x} (- 6 e^{x} cos (yz))

- 6 cos (yz) e^{x}

Solution steps

\frac{\partial}{\partial x} (- 6 e^{x} cos (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 cos (yz) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - 6 cos (yz) e^{x}

x \to 1 lim (\frac{x ^{4} - 6 x ^{2} + 8 x - 3}{x ^{4} - 2 x ^{3} + 2 x - 1})

\int_{0}^{2} 2 π (9 - x) (8 - x^{3}) d x

\int_{120}^{150} 0.1281 \cdot x \cdot e^{- \frac{x}{100}} d x

4 y + y^{^{''}} = 0

(\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 9 x^{3})

What is (\partial)/(\partial x)(-6e^xcos(yz)) ?
The answer to (\partial)/(\partial x)(-6e^xcos(yz)) is -6cos(yz)e^x