What is the sum from n=1 to infinity of n^{-2.4} ?

The sum from n=1 to infinity of n^{-2.4} is converges

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sum from n=1 to infinity of n^{-2.4}

n = 1 \sum \infty n^{- 2.4}

converges

Solution steps

n = 1 \sum \infty n^{- 2.4}

Apply Series Integral Test:

converges

= converges

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What is the sum from n=1 to infinity of n^{-2.4} ?
The sum from n=1 to infinity of n^{-2.4} is converges