What is the solution for (dy)/(dt)+2(t+1)y^2=0 ?

The solution for (dy)/(dt)+2(t+1)y^2=0 is y=-1/(-t^2-2t+c_{1)}

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(dy)/(dt)+2(t+1)y^2=0

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0

y = - \frac{1}{- t ^{2} - 2 t + c _{1}}

Solution steps

\frac{d y}{d t} + 2 (t + 1) y^{2} = 0

Solve separable ODE:

y = - \frac{1}{- t ^{2} - 2 t + c _{1}}

y = - \frac{1}{- t ^{2} - 2 t + c _{1}}

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x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}

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What is the solution for (dy)/(dt)+2(t+1)y^2=0 ?
The solution for (dy)/(dt)+2(t+1)y^2=0 is y=-1/(-t^2-2t+c_{1)}