What is the limit as x approaches 0 of (4x^2-3x)/(x^2+0.8x+4/x) ?

The limit as x approaches 0 of (4x^2-3x)/(x^2+0.8x+4/x) is 0

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limit as x approaches 0 of (4x^2-3x)/(x^2+0.8x+4/x)

x \to 0 lim (\frac{4 x ^{2} - 3 x}{x ^{2} + 0.8 x + \frac{4}{x}})

0

Solution steps

x \to 0 lim (\frac{4 x ^{2} - 3 x}{x ^{2} + 0.8 x + \frac{4}{x}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{4 x ^{2} - 3 x}{x ^{2} + 0.8 x + \frac{4}{x}}) = 0

x \to 0 + lim (\frac{4 x ^{2} - 3 x}{x ^{2} + 0.8 x + \frac{4}{x}}) = 0

= 0

(\frac{x + 8}{x - 8})^{5}

e^{x} ln (x)

n = 1 \sum \infty \frac{1}{n ^{2} + 7 n}

F (x) = (x^{4} + 9 x^{2} - 7)^{8}

What is the limit as x approaches 0 of (4x^2-3x)/(x^2+0.8x+4/x) ?
The limit as x approaches 0 of (4x^2-3x)/(x^2+0.8x+4/x) is 0