What is (\partial)/(\partial x)(x^{1/2}*y^{1/2}*z) ?

The answer to (\partial)/(\partial x)(x^{1/2}*y^{1/2}*z) is (zy^{1/2})/(2x^{1/2)}

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(\partial)/(\partial x)(x^{1/2}y^{1/2}z)

\frac{\partial}{\partial x} (x^{\frac{1}{2}} \cdot y^{\frac{1}{2}} \cdot z)

\frac{z y ^{\frac{1}{2}}}{2 x ^{\frac{1}{2}}}

Solution steps

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{1}{2}} z)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{\frac{1}{2}} z \frac{\partial}{\partial x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{\frac{1}{2}} z \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

y^{\frac{1}{2}} z \frac{1}{2} x^{\frac{1}{2} - 1} : \frac{z y ^{\frac{1}{2}}}{2 x ^{\frac{1}{2}}}

= \frac{z y ^{\frac{1}{2}}}{2 x ^{\frac{1}{2}}}

n = 1 \sum \infty \frac{( n ^{3} )}{3 ^{n^{2}}}

\frac{d y}{d x} = e^{- 2 y}

y^{^{''}} - 4 y^{^{'}} + 7 y = t e^{t}

f (x) = \frac{2 x ln ( x ) + x ^{2} - 1}{x - 1}

x \to 0 + lim ((1 + x)^{\frac{5}{x}})

What is (\partial)/(\partial x)(x^{1/2}*y^{1/2}*z) ?
The answer to (\partial)/(\partial x)(x^{1/2}*y^{1/2}*z) is (zy^{1/2})/(2x^{1/2)}