What is the limit as x approaches 0 of 8/x-8/(x^2+x) ?

The limit as x approaches 0 of 8/x-8/(x^2+x) is 8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 8/x-8/(x^2+x)

x \to 0 lim (\frac{8}{x} - \frac{8}{x ^{2} + x})

8

Solution steps

x \to 0 lim (\frac{8}{x} - \frac{8}{x ^{2} + x})

Simplify

\frac{8}{x} - \frac{8}{x ^{2} + x} : \frac{8}{x + 1}

= x \to 0 lim (\frac{8}{x + 1})

Plug in the value

x = 0

= \frac{8}{0 + 1}

Simplify

= 8

\int x^{2} - 6 xx d x

\frac{d y}{d x} = 14 x + y - 14

\frac{d}{d x} (x^{2} + y^{2} - 6 x - 4 y - 21)

\frac{d}{d x} (\frac{e + 5 x}{cos ( e ^{4 x} )})

\int cos^{2} (x) sin^{5} (x) d x

What is the limit as x approaches 0 of 8/x-8/(x^2+x) ?
The limit as x approaches 0 of 8/x-8/(x^2+x) is 8