What is (\partial)/(\partial y)(3xy-4x^2y) ?

The answer to (\partial)/(\partial y)(3xy-4x^2y) is 3x-4x^2

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(\partial)/(\partial y)(3xy-4x^2y)

\frac{\partial}{\partial y} (3 x y - 4 x^{2} y)

3 x - 4 x^{2}

Solution steps

\frac{\partial}{\partial y} (3 x y - 4 x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x y) - \frac{\partial}{\partial y} (4 x^{2} y)

\frac{\partial}{\partial y} (3 x y) = 3 x

\frac{\partial}{\partial y} (4 x^{2} y) = 4 x^{2}

= 3 x - 4 x^{2}

\int_{0}^{\frac{3}{5}} 9 - 25 x^{2} d x

e^{- s} (\frac{1}{s ^{2}})

\int sin^{2} (3 x) d x

\int_{- 1}^{2} x d x

cos (x + \frac{π}{2})

What is (\partial)/(\partial y)(3xy-4x^2y) ?
The answer to (\partial)/(\partial y)(3xy-4x^2y) is 3x-4x^2