What is the derivative of y=3x(a^2-x^2) ?

The derivative of y=3x(a^2-x^2) is 3(a^2-3x^2)

What is the first derivative of y=3x(a^2-x^2) ?

The first derivative of y=3x(a^2-x^2) is 3(a^2-3x^2)

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derivative of

y = 3 x (a^{2} - x^{2})

3 (a^{2} - 3 x^{2})

Solution steps

\frac{d}{d x} (3 x (a^{2} - x^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x (a^{2} - x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = a^{2} - x^{2}

= 3 (\frac{d x}{d x} (a^{2} - x^{2}) + \frac{d}{d x} (a^{2} - x^{2}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (a^{2} - x^{2}) = - 2 x

= 3 (1 \cdot (a^{2} - x^{2}) + (- 2 x) x)

Simplify

3 (1 \cdot (a^{2} - x^{2}) + (- 2 x) x) : 3 (a^{2} - 3 x^{2})

= 3 (a^{2} - 3 x^{2})

4 (1 + e^{- 0.3 t})

\int \frac{( ln ( x ) ) ^{3}}{2 x} d x

\frac{\partial}{\partial x} (cos (x) sin (x))

(\frac{1}{2}, 7), (3, - \frac{3}{2})

f (t) = \frac{( t ^{2} - 4 t )}{t + 3}

What is the derivative of y=3x(a^2-x^2) ?
The derivative of y=3x(a^2-x^2) is 3(a^2-3x^2)
What is the first derivative of y=3x(a^2-x^2) ?
The first derivative of y=3x(a^2-x^2) is 3(a^2-3x^2)