What is area x^4-9x^2,x^2-9,0,3 ?

The answer to area x^4-9x^2,x^2-9,0,3 is 392/15

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area x^4-9x^2,x^2-9,0,3

area

x^{4} - 9 x^{2}, x^{2} - 9, 0, 3

\frac{392}{15}

Decimal Notation

26.13333 \dots

Solution steps

Apply the area formula:

\int_{0}^{3} x^{4} - 9 x^{2} - (x^{2} - 9) d x

Solve

\int_{0}^{3} x^{4} - 9 x^{2} - (x^{2} - 9) d x : \frac{392}{15}

The area is:

= \frac{392}{15}

\int \frac{x}{x ^{2} + 64} d x

\frac{d y}{d x} = 7 y^{2} sin (x)

\int \frac{e ^{x}}{2 + e ^{x}} d x

\frac{\partial}{\partial x} (x e^{2 x y})

x y^{2} \frac{d y}{d x} = y^{3} - x^{3}, y (1) = 1

What is area x^4-9x^2,x^2-9,0,3 ?
The answer to area x^4-9x^2,x^2-9,0,3 is 392/15