What is the solution for (dy}{dx}=\frac{y+sqrt(x^2+y^2))/x ?

The solution for (dy}{dx}=\frac{y+sqrt(x^2+y^2))/x is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{y+sqrt(x^2+y^2))/x

\frac{d y}{d x} = \frac{y + x ^{2} + y ^{2}}{x}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

Solution steps

\frac{d y}{d x} = \frac{y + x ^{2} + y ^{2}}{x}

Solve using substitution:

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

\frac{d}{d x} ((2 x^{3} - 5) (x^{2} - 5 ln (x)))

\frac{d}{d x} (\frac{x}{csc ( x )})

f^{^{'}} (x) = \frac{e ^{x}}{x}

\frac{\partial}{\partial y} (3 z e^{x y})

\int \frac{2 x + 32}{x ^{2} + 8 x + 7} d x

What is the solution for (dy}{dx}=\frac{y+sqrt(x^2+y^2))/x ?
The solution for (dy}{dx}=\frac{y+sqrt(x^2+y^2))/x is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2