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Popular >

derivative of y=8sqrt(x)+6x^{3/4}

Solution

derivative of

y = 8 x + 6 x^{\frac{3}{4}}

Solution

\frac{4}{x ^{\frac{1}{2}}} + \frac{9}{2 x ^{\frac{1}{4}}}

Solution steps

\frac{d}{d x} (8 x + 6 x^{\frac{3}{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (6 x^{\frac{3}{4}})

\frac{d}{d x} (8 x) = \frac{4}{x ^{\frac{1}{2}}}

\frac{d}{d x} (6 x^{\frac{3}{4}}) = \frac{9}{2 x ^{\frac{1}{4}}}

= \frac{4}{x ^{\frac{1}{2}}} + \frac{9}{2 x ^{\frac{1}{4}}}

Popular Examples

(dy)/(dt)= t/(t^2y+y),y(0)=-9

\frac{d y}{d t} = \frac{t}{t ^{2} y + y}, y (0) = - 9

(\partial)/(\partial z)(x^2-xyz)

\frac{\partial}{\partial z} (x^{2} - x yz)

y^{''}-y^'-42y=0

y^{^{''}} - y^{^{'}} - 42 y = 0

derivative of (3x+2^x)

\frac{d}{d x} ((3 x + 2)^{x})

y^{''}+y^'+4y=0

y^{^{''}} + y^{^{'}} + 4 y = 0

Frequently Asked Questions (FAQ)

What is the derivative of y=8sqrt(x)+6x^{3/4} ?
The derivative of y=8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}
What is the first derivative of y=8sqrt(x)+6x^{3/4} ?
The first derivative of y=8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}