What is the limit as x approaches 1 of x(x-1)ln(x+1) ?

The limit as x approaches 1 of x(x-1)ln(x+1) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of x(x-1)ln(x+1)

x \to 1 lim (x (x - 1) ln (x + 1))

0

Solution steps

x \to 1 lim (x (x - 1) ln (x + 1))

Plug in the value

x = 1

= 1 \cdot (1 - 1) ln (1 + 1)

Simplify

= 0

\int (2 x^{2})^{2} d x

\frac{1}{2} e^{t} - \frac{1}{2} cos (t) - \frac{1}{2} sin (t)

2 e^{2 t}

y = x - 2, x = y^{2}

\int_{- 1}^{1} (1 - x^{2})^{\frac{3}{2}} d x

What is the limit as x approaches 1 of x(x-1)ln(x+1) ?
The limit as x approaches 1 of x(x-1)ln(x+1) is 0