What is the integral from 2 to 4 of 2x^2-3x+1 ?

The integral from 2 to 4 of 2x^2-3x+1 is 64/3

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integral from 2 to 4 of 2x^2-3x+1

\int_{2}^{4} 2 x^{2} - 3 x + 1 d x

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

\int_{2}^{4} 2 x^{2} - 3 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 2 x^{2} d x - \int_{2}^{4} 3 x d x + \int_{2}^{4} 1 d x

\int_{2}^{4} 2 x^{2} d x = \frac{112}{3}

\int_{2}^{4} 3 x d x = 18

\int_{2}^{4} 1 d x = 2

= \frac{112}{3} - 18 + 2

Simplify

\frac{112}{3} - 18 + 2 : \frac{64}{3}

= \frac{64}{3}

\frac{\partial}{\partial x} (cos (x ln (y)))

x \to + 0 + lim (\frac{36 - 4 x ^{2}}{x})

\int 2 x 2 x - 1 d x

\frac{d}{d x} (\frac{1}{6 x ^{\frac{5}{6}}})

(1, 1), (4, - \frac{1}{2})

What is the integral from 2 to 4 of 2x^2-3x+1 ?
The integral from 2 to 4 of 2x^2-3x+1 is 64/3