What is the integral of 1/(1-5x) ?

The integral of 1/(1-5x) is -1/5 ln|1-5x|+C

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integral of 1/(1-5x)

\int \frac{1}{1 - 5 x} d x

- \frac{1}{5} ln ∣ 1 - 5 x ∣ + C

Solution steps

\int \frac{1}{1 - 5 x} d x

Apply u-substitution

: \int - \frac{1}{5 u} d u

= \int - \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{5} ln ∣ u ∣

Substitute back

u = 1 - 5 x

= - \frac{1}{5} ln ∣ 1 - 5 x ∣

Add a constant to the solution

= - \frac{1}{5} ln ∣ 1 - 5 x ∣ + C

\frac{d r}{d θ} r = (7 + sec (θ)) sin (θ)

x^{2} 3 x + 5

\int \frac{x}{( x ^{2} + 7 ) ^{2}} d x

f (x) = (- 3 x^{3} + 3 x^{2})^{3}

x \to - 1 lim (arccos (x))