What is the inverse of f(x)=-4.9(t+3)^2+45.8 ?

The inverse of f(x)=-4.9(t+3)^2+45.8 is sqrt(-(10t-458)/(49))-3,-sqrt(-(10t-458)/(49))-3

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inverse of f(x)=-4.9(t+3)^2+45.8

inverse

f (x) = - 4.9 (t + 3)^{2} + 45.8

- \frac{10 t - 458}{49} - 3, - - \frac{10 t - 458}{49} - 3

Solution steps

x = - 4.9 (t + 3)^{2} + 45.8

Replace

t

with

x

t = - 4.9 (x + 3)^{2} + 45.8

Solve for

x, t = - 4.9 (x + 3)^{2} + 45.8

- \frac{10 t - 458}{49} - 3, - - \frac{10 t - 458}{49} - 3

f (x) = \frac{3}{x - 8}

4 x^{2}

5 sin (2 x)

y = sec (x + 1)

- \frac{2}{5} x^{3}

What is the inverse of f(x)=-4.9(t+3)^2+45.8 ?
The inverse of f(x)=-4.9(t+3)^2+45.8 is sqrt(-(10t-458)/(49))-3,-sqrt(-(10t-458)/(49))-3