What is the domain of f(x)=2sqrt(x+9)-4 ?

The domain of f(x)=2sqrt(x+9)-4 is x>=-9

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domain of f(x)=2sqrt(x+9)-4

domain

f (x) = 2 x + 9 - 4

x \geq - 9

Solution steps

Find non-negative values for radicals:

x \geq - 9

The function domain

x \geq - 9

f (x) = \frac{3 x ^{2} - 5 x - 2}{x + 3}

f (x) = x^{2} - 1, x \leq 0

f (x) = - \frac{2}{3} csc (2 x)

f (x) = \frac{1}{x} + 1

3 x^{2} - 2

What is the domain of f(x)=2sqrt(x+9)-4 ?
The domain of f(x)=2sqrt(x+9)-4 is x>=-9