What is the critical f(x)=-6sin(-x+pi/2) ?

The critical f(x)=-6sin(-x+pi/2) is x=2pin,x=pi+2pin

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critical f(x)=-6sin(-x+pi/2)

critical points

f (x) = - 6 sin (- x + \frac{π}{2})

x = 2 πn, x = π + 2 πn

Solution steps

- 6 sin (- x + \frac{π}{2})

Find where

f^{'} (x)

is equal to zero or undefined

x = 2 πn, x = π + 2 πn

Identify critical points not in

f (x)

domain

Domain of

- 6 sin (- x + \frac{π}{2}) : - \infty < x < \infty

All critical points are in domain

x = 2 πn, x = π + 2 πn

3 x^{2} + 2 x

f (x) = - 4^{x}

f (x) = \frac{1}{x - 3} + 2

f (x) = x^{2} - 25, x \geq 5

What is the critical f(x)=-6sin(-x+pi/2) ?
The critical f(x)=-6sin(-x+pi/2) is x=2pin,x=pi+2pin