What is the critical f(x)=(x+5)^{2/3} ?

The critical f(x)=(x+5)^{2/3} is x=-5

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critical f(x)=(x+5)^{2/3}

critical points

f (x) = (x + 5)^{\frac{2}{3}}

x = - 5

Solution steps

(x + 5)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5

Identify critical points not in

f (x)

domain

Domain of

(x + 5)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = - 5

y = 18 x - 17

f (x) = \frac{x + 3}{4 - x ^{2} - 9}

f (x) = \frac{x - 3}{x ^{2} - 9}

- 6 x

y = x^{2} - 4 x + 3