en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (5,7),(3,0)

Solution

distance

(5, 7), (3, 0)

Solution

53

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, 7)

and

(3, 0)

is

= (3 - 5)^{2} + (0 - 7)^{2}

Simplify

= 53

Popular Examples

range of f(x)=ln(x)+4 range

f (x) = ln (x) + 4

periodicity of-2cos(4pix)periodicity

- 2 cos (4 π x)

symmetry y=-6x^2-6x symmetry

y = - 6 x^{2} - 6 x

inverse of f(x)=((e^x-e^{-x}))/2 inverse

f (x) = \frac{( e ^{x} - e ^{- x} )}{2}

domain of f(x)=-x^2+3x+5 domain

f (x) = - x^{2} + 3 x + 5

Frequently Asked Questions (FAQ)

What is the distance (5,7),(3,0) ?
The distance (5,7),(3,0) is square root of 53