What is the intercepts of f(x)=(x+6)/(x^2-3x-18) ?

The intercepts of f(x)=(x+6)/(x^2-3x-18) is X Intercepts: (-6,0),Y Intercepts: (0,-1/3)

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intercepts of f(x)=(x+6)/(x^2-3x-18)

intercepts

f (x) = \frac{x + 6}{x ^{2} - 3 x - 18}

X Intercepts : (- 6, 0), Y Intercepts : (0, - \frac{1}{3})

Solution steps

x -

axis interception points of

\frac{x + 6}{x ^{2} - 3 x - 18} : (- 6, 0)

y -

axis interception point of

\frac{x + 6}{x ^{2} - 3 x - 18} : (0, - \frac{1}{3})

X Intercepts : (- 6, 0), Y Intercepts : (0, - \frac{1}{3})

\frac{4}{( x + 1 ) ^{2} - 1}

f (x) = \frac{( x ^{2} + 25 )}{x}

y = 4 x + 3

f (x) = \frac{1}{1 + e ^{x}}

f (x) = lo g_{\frac{1}{2}} (x)

What is the intercepts of f(x)=(x+6)/(x^2-3x-18) ?
The intercepts of f(x)=(x+6)/(x^2-3x-18) is X Intercepts: (-6,0),Y Intercepts: (0,-1/3)