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Popular >

midpoint (3,4),(8,-4)

Solution

midpoint

(3, 4), (8, - 4)

Solution

(\frac{11}{2}, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, 4), (x_{2}, y_{2}) = (8, - 4)

= (\frac{8 + 3}{2}, \frac{- 4 + 4}{2})

Refine

= (\frac{11}{2}, 0)

Popular Examples

range of 3x^2+5 range

3 x^{2} + 5

domain of f(x)=3(x-1)^2-2 domain

f (x) = 3 (x - 1)^{2} - 2

inverse of x-7 inverse

x - 7

y = x^{2} - x - 2

critical f(x)=(3x+1)/(3x)critical points

f (x) = \frac{3 x + 1}{3 x}

Frequently Asked Questions (FAQ)

What is the midpoint (3,4),(8,-4) ?
The midpoint (3,4),(8,-4) is (11/2 ,0)