What is the domain of f(x)= 2/(x^2+2x) ?

The domain of f(x)= 2/(x^2+2x) is x 0

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domain of f(x)= 2/(x^2+2x)

domain

f (x) = \frac{2}{x ^{2} + 2 x}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

\frac{x ^{2} - 2 x - 3}{x}

f (x) = \frac{1}{4} x + 7

f (x) = 0.6 x^{2} - 1.5 x + 1

f (x) = \frac{( x + 1 )}{( x + 7 )}

f (x) = x^{2} + 1

What is the domain of f(x)= 2/(x^2+2x) ?
The domain of f(x)= 2/(x^2+2x) is x<-2\lor-2<x<0\lor x>0