What is the extreme y=x^3-2x^2-4x+3 ?

The extreme y=x^3-2x^2-4x+3 is Maximum(-2/3 , 121/27),Minimum(2,-5)

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extreme y=x^3-2x^2-4x+3

extreme points

y = x^{3} - 2 x^{2} - 4 x + 3

Maximum (- \frac{2}{3}, \frac{121}{27}), Minimum (2, - 5)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x + 3 : \frac{121}{27}

Maximum (- \frac{2}{3}, \frac{121}{27})

Plug

x = 2

into

x^{3} - 2 x^{2} - 4 x + 3 : - 5

Minimum (2, - 5)

Maximum (- \frac{2}{3}, \frac{121}{27}), Minimum (2, - 5)

f (x) = 4 x - 12

f (x) = \frac{( x + 2 )}{( x ^{2} - x - 6 )}

\frac{3 x ^{2} + 1}{x ^{2} - 2 x - 3}

tan^{3} (x) d x

7 x^{2} - 40 x - 25

What is the extreme y=x^3-2x^2-4x+3 ?
The extreme y=x^3-2x^2-4x+3 is Maximum(-2/3 , 121/27),Minimum(2,-5)