What is the domain of f(x)=sqrt(x^2-5x-6) ?

The domain of f(x)=sqrt(x^2-5x-6) is x = 6

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domain of f(x)=sqrt(x^2-5x-6)

domain

f (x) = x^{2} - 5 x - 6

x \leq - 1 or x \geq 6

Interval Notation

(- \infty, - 1] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 6

The function domain

x \leq - 1 or x \geq 6

f (x) = - \frac{7 x}{6 x - 5}

f (x) = ln (x^{2} - 14 x)

(- 5, - 3), (4, - 2)

3

2 x - y = - 7

What is the domain of f(x)=sqrt(x^2-5x-6) ?
The domain of f(x)=sqrt(x^2-5x-6) is x<=-1\lor x>= 6