What is the inverse of f(x)=x^2-2,x>= 0 ?

The inverse of f(x)=x^2-2,x>= 0 is sqrt(x+2),-sqrt(x+2)

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inverse of f(x)=x^2-2,x>= 0

inverse

f (x) = x^{2} - 2, x \geq 0

x + 2, - x + 2

Solution steps

y = x^{2} - 2

Replace

x

with

y

x = y^{2} - 2

Solve for

y, x = y^{2} - 2

x + 2, - x + 2

- 4 cos (2 x)

f (x) = - 700 x + 3500

f (x) = \frac{1}{x ^{2} - 9}

f (x) = 3 x^{2} ln (\frac{x}{4})

4 x^{2} - 5 x + 7

What is the inverse of f(x)=x^2-2,x>= 0 ?
The inverse of f(x)=x^2-2,x>= 0 is sqrt(x+2),-sqrt(x+2)