What is the domain of f(x)=9+(8+x)^{1/2} ?

The domain of f(x)=9+(8+x)^{1/2} is x>=-8

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domain of f(x)=9+(8+x)^{1/2}

domain

f (x) = 9 + (8 + x)^{\frac{1}{2}}

x \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

The function domain

x \geq - 8

f (x) = 16 x^{4} - 96 x^{2}

y = 4 - x

f (x) = x^{x}

\frac{- 2 x ^{2}}{( x - 3 ) ( x + 2 )}

6 x + 2 y = - 2

What is the domain of f(x)=9+(8+x)^{1/2} ?
The domain of f(x)=9+(8+x)^{1/2} is x>=-8