What is the perpendicular 6x-y=-3,(-9,5) ?

The perpendicular 6x-y=-3,(-9,5) is y=-1/6 x+7/2

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perpendicular 6x-y=-3,(-9,5)

perpendicular

6 x - y = - 3, (- 9, 5)

y = - \frac{1}{6} x + \frac{7}{2}

Solution steps

Find the line

y = mx + b

perpendicular to

6 x - y = - 3

that passes through

(- 9, 5)

Find the slope of

6 x - y = - 3 : m = 6

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{6}

Find the line with slope m=

- \frac{1}{6}

and passing through

(- 9, 5) : y = - \frac{1}{6} x + \frac{7}{2}

y = - \frac{1}{6} x + \frac{7}{2}

\frac{6}{( x - 2 ) ^{3}}

f (x) = - ∣ x - 5 ∣ + 6

4 (x + 3)^{2} - 2

f (x) = x^{4} - 12 x^{2}

What is the perpendicular 6x-y=-3,(-9,5) ?
The perpendicular 6x-y=-3,(-9,5) is y=-1/6 x+7/2