What is the domain of (x+1)/(x^2-1) ?

The domain of (x+1)/(x^2-1) is x 1

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domain of (x+1)/(x^2-1)

domain

\frac{x + 1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

2 x + 4 y = 16

f (x) = 1 - x^{4}

f (x) = 3 x - 2 y = 6

f (x) = x - 10

\frac{x ^{2} + 3 x - 4}{x + 4}

What is the domain of (x+1)/(x^2-1) ?
The domain of (x+1)/(x^2-1) is x<-1\lor-1<x<1\lor x>1