What is the domain of f(x)=sqrt(x)+sqrt(8-x) ?

The domain of f(x)=sqrt(x)+sqrt(8-x) is 0<= x<= 8

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domain of f(x)=sqrt(x)+sqrt(8-x)

domain

f (x) = x + 8 - x

0 \leq x \leq 8

Interval Notation

[0, 8]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 8

The function domain

0 \leq x \leq 8

f (x) = x - 7 - 7

f (x) = 3.1 + 6.6 x - 2.3 x^{2}

\frac{4 x + 7}{3 x - 4}

f (x) = 3 x^{2} + 2 x - 6

y = - 2 sin (4 x + \frac{π}{2})

What is the domain of f(x)=sqrt(x)+sqrt(8-x) ?
The domain of f(x)=sqrt(x)+sqrt(8-x) is 0<= x<= 8