What is the inverse of f(x)=1-e^{-x^2 1/18} ?

The inverse of f(x)=1-e^{-x^2 1/18} is 3sqrt(2)sqrt(-ln(1-x)),-3sqrt(2)sqrt(-ln(1-x))

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inverse of f(x)=1-e^{-x^2 1/18}

inverse

f (x) = 1 - e^{- x^{2} \frac{1}{18}}

32 - ln (1 - x), - 32 - ln (1 - x)

Solution steps

y = 1 - e^{- x^{2} \frac{1}{18}}

Replace

x

with

y

x = 1 - e^{- y^{2} \frac{1}{18}}

Solve for

y, x = 1 - e^{- y^{2} \frac{1}{18}}

32 - ln (1 - x), - 32 - ln (1 - x)

f (x) = cos (2 x) - 1

f (x) = \frac{x ^{2} - 9}{x ^{2} - 2 x - 1}

f (x) = x^{3} + 8 x^{2} + 16 x + 25

4 x + 5 y = - 10

- ln (x + 3)

What is the inverse of f(x)=1-e^{-x^2 1/18} ?
The inverse of f(x)=1-e^{-x^2 1/18} is 3sqrt(2)sqrt(-ln(1-x)),-3sqrt(2)sqrt(-ln(1-x))