What is the domain of f(x)=ln^2(x^2+1) ?

The domain of f(x)=ln^2(x^2+1) is -infinity <x<infinity

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domain of f(x)=ln^2(x^2+1)

domain

f (x) = ln^{2} (x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = arcsin (6 x^{2} - 1 + ∣ x ∣)

f (x) = - \frac{3}{x + 2} - 1

f (x) = \frac{2 x + 1}{x - 3}

1200 + 400 cos (\frac{π t}{3})

f (x) = x^{2} - 10 x + 21

What is the domain of f(x)=ln^2(x^2+1) ?
The domain of f(x)=ln^2(x^2+1) is -infinity <x<infinity