What is the domain of f(x)=sqrt(x+19)-2 ?

The domain of f(x)=sqrt(x+19)-2 is x>=-19

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domain of f(x)=sqrt(x+19)-2

domain

f (x) = x + 19 - 2

x \geq - 19

Interval Notation

[- 19, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 19

The function domain

x \geq - 19

f (x) = \frac{( - 5 x + 8 )}{6 x - 10}

4 + x

f (x) = \frac{1}{x} + 7

f (x) = \frac{x + 4}{x ^{2} - 64}

y = \frac{6}{7} x + 6

What is the domain of f(x)=sqrt(x+19)-2 ?
The domain of f(x)=sqrt(x+19)-2 is x>=-19