What is the domain of (2x^2-3)/(x^2-1) ?

The domain of (2x^2-3)/(x^2-1) is x 1

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domain of (2x^2-3)/(x^2-1)

domain

\frac{2 x ^{2} - 3}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{1}{6 x ^{2} + 3}

2 sin (4 x - π)

- \frac{1}{6} cos (6 x)

\frac{18 x ^{2}}{( 2 - 3 x ^{3} ) ^{3}}

2 x + 3 y = 1470

What is the domain of (2x^2-3)/(x^2-1) ?
The domain of (2x^2-3)/(x^2-1) is x<-1\lor-1<x<1\lor x>1