What is the critical f(x)=2x^3-4x^2 ?

The critical f(x)=2x^3-4x^2 is x=0,x= 4/3

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critical f(x)=2x^3-4x^2

critical points

f (x) = 2 x^{3} - 4 x^{2}

x = 0, x = \frac{4}{3}

Solution steps

2 x^{3} - 4 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{4}{3}

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 4 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{4}{3}

y = 2 x - 1

25

f (x) = 5 x - 6

- 2 x^{2} + 2 x - 3

\frac{3}{2} + \frac{31}{2 ( 2 x - 7 )}