What is the asymptotes of f(x)=(x^2-6x)/(x^4-1296) ?

The asymptotes of f(x)=(x^2-6x)/(x^4-1296) is Vertical: x=-6,Horizontal: y=0

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asymptotes of f(x)=(x^2-6x)/(x^4-1296)

asymptotes

f (x) = \frac{x ^{2} - 6 x}{x ^{4} - 1296}

Vertical : x = - 6, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x}{x ^{4} - 1296} : x = - 6

Horizontal Asymptotes of

\frac{x ^{2} - 6 x}{x ^{4} - 1296} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 6 x}{x ^{4} - 1296} :

None

Vertical : x = - 6, Horizontal : y = 0

Y (x) = - \frac{2}{3} x + 7, (3, 3)

f (x) = - 3 x

\frac{∣ x ^{2} + x + 1 ∣}{x ^{2} - 1}

f (x) = (x + 3)^{2}, x \leq - 3

f (x) = x e^{\frac{1}{x}}

What is the asymptotes of f(x)=(x^2-6x)/(x^4-1296) ?
The asymptotes of f(x)=(x^2-6x)/(x^4-1296) is Vertical: x=-6,Horizontal: y=0