What is the inverse of f(x)=1650(1.022)^t ?

The inverse of f(x)=1650(1.022)^t is (ln(t/(1650)))/(ln(1.022))

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inverse of f(x)=1650(1.022)^t

inverse

f (x) = 1650 (1.022)^{t}

\frac{ln ( \frac{t}{1650} )}{ln ( 1.022 )}

Solution steps

x = 1650 \cdot 1.02 2^{t}

Replace

t

with

x

t = 1650 \cdot 1.02 2^{x}

Solve for

x, t = 16501.02 2^{x}

\frac{ln ( \frac{t}{1650} )}{ln ( 1.022 )}

6 - x^{2}

\frac{7 x + 6}{5 x ^{\frac{3}{5}}}

2 x^{2}

(- 4, 5), (- 8, 5)

2 x + y = 5

What is the inverse of f(x)=1650(1.022)^t ?
The inverse of f(x)=1650(1.022)^t is (ln(t/(1650)))/(ln(1.022))