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Popular >

inflection f(x)=-1/3 x^3+7x^2

Solution

inflection points

f (x) = - \frac{1}{3} x^{3} + 7 x^{2}

Solution

(7, \frac{686}{3})

Solution steps

f^{''} (x) = - 2 x + 14

Find intervals:

Concave Upward

: - \infty < x < 7,

Concave Downward

: 7 < x < \infty

Plug

x = 7

into

- \frac{1}{3} x^{3} + 7 x^{2} : \frac{686}{3}

(7, \frac{686}{3})

Popular Examples

inflection f(x)= x/(x+1)inflection points

f (x) = \frac{x}{x + 1}

periodicity of f(x)=cos(2x-pi/2)periodicity

f (x) = cos (2 x - \frac{π}{2})

intercepts of f(x)=2x+3 intercepts

f (x) = 2 x + 3

inverse of f(x)=(3x+2)/(2x-1)inverse

f (x) = \frac{3 x + 2}{2 x - 1}

parallel x+4y=-2 parallel

x + 4 y = - 2

Frequently Asked Questions (FAQ)

What is the inflection f(x)=-1/3 x^3+7x^2 ?
The inflection f(x)=-1/3 x^3+7x^2 is (7, 686/3)