What is the extreme f(x)=2x^3-15x^2-36x ?

The extreme f(x)=2x^3-15x^2-36x is Maximum(-1,19),Minimum(6,-324)

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extreme f(x)=2x^3-15x^2-36x

extreme points

f (x) = 2 x^{3} - 15 x^{2} - 36 x

Maximum (- 1, 19), Minimum (6, - 324)

Solution steps

f^{'} (x) = 6 x^{2} - 30 x - 36

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 1

into

2 x^{3} - 15 x^{2} - 36 x : 19

Maximum (- 1, 19)

Plug

x = 6

into

2 x^{3} - 15 x^{2} - 36 x : - 324

Minimum (6, - 324)

Maximum (- 1, 19), Minimum (6, - 324)

2 y + x - 4 = 0

(0.11) (12.11)

f (x) = - 0.01 (x - 20)^{2} + 50

lo g_{6} (x - 1) - 5

f (x) = \frac{x ^{7} + 5}{7} - 2

What is the extreme f(x)=2x^3-15x^2-36x ?
The extreme f(x)=2x^3-15x^2-36x is Maximum(-1,19),Minimum(6,-324)