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Popular >

extreme f(x)=x^2+8x+6

Solution

extreme points

f (x) = x^{2} + 8 x + 6

Solution

Minimum (- 4, - 10)

Solution steps

f^{'} (x) = 2 x + 8

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{2} + 8 x + 6 : - 10

Minimum (- 4, - 10)

Popular Examples

extreme f(x)=(e^x)/(x^2)extreme points

f (x) = \frac{e ^{x}}{x ^{2}}

inverse of f(x)=-(x-4)^2+6 inverse

f (x) = - (x - 4)^{2} + 6

slope of y=2x+8 slope

y = 2 x + 8

asymptotes of y=-cot(2x-pi/4)asymptotes

y = - cot (2 x - \frac{π}{4})

intercepts of (x-4)^3+6 intercepts

(x - 4)^{3} + 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+8x+6 ?
The extreme f(x)=x^2+8x+6 is Minimum(-4,-10)