What is the domain of f(x)= 1/(\sqrt[4]{x^2-7x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-7x)} is x 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(\sqrt[4]{x^2-7x)}

domain

x < 0 or x > 7

Interval Notation

(- \infty, 0) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 7

Find undefined (singularity) points:

x = 7, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 7

f (x) = - 4 x

y = - 7 x + 2

\frac{x ^{2} + x - 12}{x - 3}

\frac{3 x}{( x + 2 ) ^{2}}

y = 4 x^{2} + 8 x - 1

What is the domain of f(x)= 1/(\sqrt[4]{x^2-7x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-7x)} is x<0\lor x>7