What is the inverse of f(x)=x^2+4x+3 ?

The inverse of f(x)=x^2+4x+3 is -2+sqrt(x+1),-sqrt(x+1)-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2+4x+3

inverse

f (x) = x^{2} + 4 x + 3

- 2 + x + 1, - x + 1 - 2

Solution steps

y = x^{2} + 4 x + 3

Replace

x

with

y

x = y^{2} + 4 y + 3

Solve for

y, x = y^{2} + 4 y + 3

- 2 + x + 1, - x + 1 - 2

y = 8 x^{3}

f (x) = x^{2} + 4

\frac{4}{3} x^{3}

f (x) = \frac{1}{x ^{3}}

\frac{x}{x ^{2} - 4}

What is the inverse of f(x)=x^2+4x+3 ?
The inverse of f(x)=x^2+4x+3 is -2+sqrt(x+1),-sqrt(x+1)-2