What is the parity f(x)=((x^2+1))/((x-1)) ?

The parity f(x)=((x^2+1))/((x-1)) is Neither even nor odd

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parity f(x)=((x^2+1))/((x-1))

parity

f (x) = \frac{( x ^{2} + 1 )}{( x - 1 )}

Neither even nor odd

Solution steps

f (- x) : \frac{x ^{2} + 1}{- x - 1}

- f (x) : - \frac{x ^{2} + 1}{x - 1}

Check parity of

\frac{x ^{2} + 1}{x - 1}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = - 10 csc (x)

f (x) = - x^{3}

(- 5, - 1), (- 8, - 7)

y = - \frac{1}{3} x + 4

y = 5 x + 3

What is the parity f(x)=((x^2+1))/((x-1)) ?
The parity f(x)=((x^2+1))/((x-1)) is Neither even nor odd