What is the critical f(x)=x^4-16x^3+22x^2 ?

The critical f(x)=x^4-16x^3+22x^2 is x=0,x=1,x=11

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critical f(x)=x^4-16x^3+22x^2

critical points

f (x) = x^{4} - 16 x^{3} + 22 x^{2}

x = 0, x = 1, x = 11

Solution steps

x^{4} - 16 x^{3} + 22 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 1, x = 11

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 16 x^{3} + 22 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 1, x = 11

\frac{x ^{2} + 5 x + 6}{x - 1}

f (x) = \frac{x + 1}{x - 4}

- \frac{5}{3}

x^{2} - x - 6

f (x) = 1 - 5 x^{2}

What is the critical f(x)=x^4-16x^3+22x^2 ?
The critical f(x)=x^4-16x^3+22x^2 is x=0,x=1,x=11