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Popular >

extreme f(x)=x^2-x-4

Solution

extreme points

f (x) = x^{2} - x - 4

Solution

Minimum (\frac{1}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

x^{2} - x - 4 : - \frac{17}{4}

Minimum (\frac{1}{2}, - \frac{17}{4})

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f (x) = 3 x^{2} - 1

intercepts of f(x)=ln(x-1)-1 intercepts

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domain of f(x)=log_{0.5}(x)domain

f (x) = lo g_{0.5} (x)

range of sqrt(-x)range

- x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-x-4 ?
The extreme f(x)=x^2-x-4 is Minimum(1/2 ,-17/4)