What is the range of f(x)=arcsin(x) ?

The range of f(x)=arcsin(x) is -pi/2 <= f(x)<= pi/2

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range of f(x)=arcsin(x)

range

f (x) = arcsin (x)

- \frac{π}{2} \leq f (x) \leq \frac{π}{2}

Interval Notation

[- \frac{π}{2}, \frac{π}{2}]

Solution steps

The range of the basic

arcsin

function is

- \frac{π}{2} \leq arcsin (x) \leq \frac{π}{2}

- \frac{π}{2} \leq arcsin (x) \leq \frac{π}{2}

Therefore the range is

- \frac{π}{2} \leq f (x) \leq \frac{π}{2}

f (x) = - \frac{1}{3} (x - 1)^{2} + 1

3 x - 4 y = 12

\frac{x ^{2}}{x ^{2} - 9}

x - 1 \cdot 5 x + 3

2 x + y = 9

What is the range of f(x)=arcsin(x) ?
The range of f(x)=arcsin(x) is -pi/2 <= f(x)<= pi/2